Question

if the distance time graph of anHow many molecules are present in? 17 g. of NH3 (Atomic mass of H=1, N=14u)

Answer 1

Answer:

M,Molar mass of NH₃=14+(1×3)=17

m,Given mass=100 g

n,number of moles=m/M=100/17

n=N/N₀

N=n×N₀=(100/17)×6.022×10²³

=3.55×10²⁴

M,Molar mass of N₂=14×2=28

m,Given mass=100 g

n,number of moles=m/M=100/28

n=N/N₀

N=n×N₀

(100/28)×6.022×10²³=2.15×10²⁴

∴Number of molecules in 100 g of NH3 is more than 100 g of N2.

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