If the distance travelled by a body in the
nth second is given by (4 + 6 n) m, then
find the initial velocity and acceleration
of the body respectively.
Answers
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0
Answer:
s
nth
=u+
2
a
(2n−1)
4+6n=u+
2
a
(2n−1)
=(u−
2
a
)+an
a=6m/s
2
u−
2
a
=4
u−3=4
u=7m/s
Explanation:
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