Question

If the distance travelled by a body in the
nth
seconds is given by (12 + 8n) m, then
find the initial velocity and acceleration
of the body respectively.​

Answer 1

Answer:

Hello dear mate...⚘

Explanation:

distance covered in nth second

S=4+6n .......1

also

S=u+a(2n-1)/2 .........2

differentiating equation 1 with respect to n

dS/dn=0+6

dS/dn=6 ......3

differentiating equation second with respect to n

dS/dn=0+a

dS/dn=a

putting value of dS/dn

a=6m/s^2

put the value of a in equation 2

and equate equation 1 and 2

4+6n=u+6(2n-1)/2

4+6n=6n-3+u

u=7m/s