Physics, asked by ashok20, 1 year ago

if the distance travelled by a freely falling body in the last second of its journey is equal to distance travelled in the first 2s, the time of descent of the body is

Answers

Answered by JunaidMirza
157
Distance travelled in 1st 2 seconds
S = 0.5at^2
= 0.5g (2^2)
= 2g

Distance travelled in last second
S = g(n - 1/2)
Is it given that S = 2g
2g = g(n - 1/2)
n = 2 + 1/2
n = 2.5 second

Time of fall is 2.5 seconds
Answered by lokanathkuppan
7

Answer:

2.5 second

Explanation:

फाइंड डिस्टेंस ट्रैवल्ड इज इन फर्स्ट 2 सेकंड ग्रेड फाइंड डिस्टेंस ट्रैवल्ड इन द फर्स्ट टू सेकंड एंड डिस्टेंस ट्रैवल्ड इन लास्ट सेकंड दिन वी कैन गेट द आंसर

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