Question

if the distance travelled by a freely falling body in the last second of its journey is equal to distance travelled in the first 2s, the time of descent of the body is

Answer 1

Distance travelled in 1st 2 seconds
S = 0.5at^2
= 0.5g (2^2)
= 2g

Distance travelled in last second
S = g(n - 1/2)
Is it given that S = 2g
2g = g(n - 1/2)
n = 2 + 1/2
n = 2.5 second

Time of fall is 2.5 seconds

Answer 2

Answer:

2.5 second

Explanation:

फाइंड डिस्टेंस ट्रैवल्ड इज इन फर्स्ट 2 सेकंड ग्रेड फाइंड डिस्टेंस ट्रैवल्ड इन द फर्स्ट टू सेकंड एंड डिस्टेंस ट्रैवल्ड इन लास्ट सेकंड दिन वी कैन गेट द आंसर