if the distance travelled is given in respect with time S= At^3+ Bt^2 +C, find the dimension of A,B,C
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Explanation:
Given that,
x=a+bt+ct
2
+dt
3
x is the displacement.
Now, by principle of homogeneity
a=bt=ct
2
=dt
3
=x
Now, a=L
[bt]=[L]
b=[LT
−1
]
c=[LT
−2
]
d=[LT
−3
]
Hence, the dimension of a, b, c and d is [L],[LT
−1
],[LT
−2
]and[LT
−3
]
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