Question

if the distance travelled is given in respect with time S= At^3+ Bt^2 +C, find the dimension of A,B,C ​

Answer 1

Explanation:

Given that,

x=a+bt+ct

2

+dt

3

x is the displacement.

Now, by principle of homogeneity

a=bt=ct

2

=dt

3

=x

Now, a=L

[bt]=[L]

b=[LT

−1

]

c=[LT

−2

]

d=[LT

−3

]

Hence, the dimension of a, b, c and d is [L],[LT

−1

],[LT

−2

]and[LT

−3

]