If the division 1234x ÷ 3 leaves a remainder of 1. What might be the values of x?
[i already know the answer..its 0,3,6 and 9.. but dont know the steps..so plz provide steps]
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If the division 1234x ÷ 3 leaves a remainder of 1. What might be the values of x?
1+2+3+4=13
24=
13/3 = the result is 4 and reminder is one.
so, the value of x can be 0,3,6 and 9.
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