If the dot product of two vectors is 3 times the magnitude of their
cross product, calculate the angle between the two vectors
Answers
Answered by
0
Answer:
Explanation:cot inverse 1/3
Answered by
1
Answer:
dot product=abcosx
sin product=ab sinx
a/q
ab cosx=3absinx
cot x=3
x=cot^-1(3)
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