Question

If the doubling time of an organism is 0.693h, the specific growth rate will be.​

Answer 1

Answer:

For example, with an annual growth rate of 4.8% the doubling time is 14.78 years, and a doubling time of 10 years corresponds to a growth rate between 7% and 7.5% (actually about 7.18%).

Answer 2

Answer: The specific time (µ) will be 0.0166666

Given:

Doubling time = 0.693 hours

Changing it to minutes, we get

Doubling time = 41.58 minutes.

And we know that,

Ln2 = 0.693

(where, LN2, the natural logarithm of 2, is a constant)

To find:

The specific growth rate, µ

Solution:

In order to find the specific growth rate (µ), the ln2 is divided by the doubling time,

So,

Specific growth rate (µ) = ln 2/ Doubling time

Specific growth (µ) = 0.693/41.58

So,

µ = 0.0166666

Hence, the specific time (µ) will be 0.0166666

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