Chemistry, asked by maiyuriskannan, 7 months ago

If the e.m.f of the net redox reaction is positive, its ∆G is

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Answered by manishpandey9554
1

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hey dude here is your answer...

Free energy and the equilibrium constant (this is from the section on thermodynamics)

Free energy and the equilibrium constant (this is from the section on thermodynamics)DG = DG0 + RT lnQ

Free energy and the equilibrium constant (this is from the section on thermodynamics)DG = DG0 + RT lnQwhere Q is the reaction quotient

The EMF of a redox reaction in a voltaic cell is determined not only by the type of redox reaction, but also the concentrations of the reactants and products (i.e. the reducing agent and oxidizing agent)

The EMF of a redox reaction in a voltaic cell is determined not only by the type of redox reaction, but also the concentrations of the reactants and products (i.e. the reducing agent and oxidizing agent)The EMF of the cell will fall as the reactants are used up and products increase in concentration

The EMF of a redox reaction in a voltaic cell is determined not only by the type of redox reaction, but also the concentrations of the reactants and products (i.e. the reducing agent and oxidizing agent)The EMF of the cell will fall as the reactants are used up and products increase in concentrationAt equilibrium concentrations of reactants and products, the EMF = 0. Electrons flow spontaneously in a redox reaction because the system is attempting to achieve equilibrium. When equilibrium is achieved, net electron flow is zero.

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