Question

if the each edges of cube is doubled how many times period surface area in Greek

Answer 1

surface area of cube(s1)=6l^2 ( whre l=length of edge)
when each edge double that is l=2l
then,
surface area of cube=6×(2l)^2
=6×4l^2=4(6l^2)
=4×s1
so, when the length of sides become double surface area becomes 4 times the real surface area.

Answer 2

Let the edge of given cube be l and new edge be 2l .
SA of given cube = 6lsq.
new cube= 6x2lsq
Sa of given ÷ sa of new cube
= 6 2L2 ÷ 6l2
=4 times