Physics, asked by Sonugoutam4373, 7 months ago

If the earth shrinks to 50 percentage of its real radius its mass remaining the same , the weight of a body on the earth will

Answers

Answered by monalisan099
0

Explanation:

we know that g=GM/R² hence g is inversely proportional to R² so if earth shrinks 50 percentage of its real radius

then g becomes 4 times it's real value so as the mass the mass of the body is always constant hence weight of a body depends on g so weight also become 4 times if it's real value

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