Question

if the earth strings to 50% of its real radius its mass remaining the same the weight of a body on the earth will be​

Answer 1

Answer:

As the mass of the earth remains same, so initially the gravitational acceleration,

g=

R

2

GM

and after shrinks g

′

=

(R/2)

2

GM

=4g

% change in weight =

mg

mg

′

−mg

×100=

g

g

′

−g

×=

g

4g−g

×100=300 %.

Answer 2

Explanation:

a/c to question, The earth shrinks 50% of its real radius . hence, weight of body will be (1/4)th of weight of body when radius of earth is real....