Question

if the edge of a cube is increased by 50% the percentage increases in the surface area

Answer 1

Surface area of cube =6l2 increases by 50% 6(l×[50/100×l])2

Answer 2

let initial edge be 10(a1)
final edge =150% of 10=15(a2)
% increase in surface area
=6(a2^2)-6(a1^2)/6(a1^2)×100
=225-100/100×100
=225-100=125%