if the edge of a cube is tripled find the ratio of surface area and that of volume of the two cubes
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let the edge of the cube 1 be x
so surface area cube 1 = 6*x*x
and volume will be x*x*x
given the edge of the new cube is 3x
so the surface area of the new cube is 6*3x*3x
volume =3x*3x*3x
ratio of surface area = (6*x*x)/(6*3x*3x) = 1/9 , so ratio = 1:9
ratio of volume = (x*x*x)/(3x*3x*3x) = 1/27 , so ratio = 1:27
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