if the edge of double find percentage increase in the surface area
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percentage increase in its total surface area 300%
Explanation
Surface area of a cube with side 'a' can be written as
Surface area A =6a^2
If each edge of a cube is doubled, side of cube a becomes 2a
Therefore, Surface area A =6a^2 = 6 (2a)^2 = 24a^2
then the percentage increase in its total surface area =[ (difference of surface area) x 100]/initial surface area
Difference of surface area= 24a^2 - 6a^2=18a^2
percentage increase in its total surface area = (18a^2 x 100)/6a^2 300%
Hope this helps...!
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Let edge = x area = 6x^2
If edge isn’t doubled than edge = 2x
Area = 6 (2x) ^2 = 24x^2
So increase in area = 24x^2-6x^2= 18x^2
% increase =18x^2/3x^2 x100 = 300%
If edge isn’t doubled than edge = 2x
Area = 6 (2x) ^2 = 24x^2
So increase in area = 24x^2-6x^2= 18x^2
% increase =18x^2/3x^2 x100 = 300%
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