if the edge of the cube increased by 20% . then find the percentage increased in its volume
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Answered by
7
Hi ,
Let the edge of the cube = a = 10 units
Volume ( v ) = a³
v = ( 10 )³
v = 1000 cubic units ----( 1 )
If edge is increased by 20% then
edge of the new cube = s = 12units
Volume ( V ) = ( 12 )³ cubic units---( 2 )
Difference = V - v
= ( 12 )³ - ( 10)³
= ( 12 - 10 ) [ 12² + 120 + 100 ]
= 2 × 364
= 728 cubic units
Increase in volume is
1000 cubic units = 728 cubic units
100 cubic units ------x cubic units
x = ( 728 × 100 ) / 1000
x = 72.8 %
Increased percentage = x = 72.8%
I hope this helps you.
:)
Let the edge of the cube = a = 10 units
Volume ( v ) = a³
v = ( 10 )³
v = 1000 cubic units ----( 1 )
If edge is increased by 20% then
edge of the new cube = s = 12units
Volume ( V ) = ( 12 )³ cubic units---( 2 )
Difference = V - v
= ( 12 )³ - ( 10)³
= ( 12 - 10 ) [ 12² + 120 + 100 ]
= 2 × 364
= 728 cubic units
Increase in volume is
1000 cubic units = 728 cubic units
100 cubic units ------x cubic units
x = ( 728 × 100 ) / 1000
x = 72.8 %
Increased percentage = x = 72.8%
I hope this helps you.
:)
Answered by
2
let the edge be a
volume=a3 (cube)
20%of a =1/5a
Increased egde bg 20%=1/5a +a=6/5a
change in volume =6/5a-a=a3/5
Change of volume %=a3/5/a3×100=20%
volume=a3 (cube)
20%of a =1/5a
Increased egde bg 20%=1/5a +a=6/5a
change in volume =6/5a-a=a3/5
Change of volume %=a3/5/a3×100=20%
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