Math, asked by ramkaname, 4 months ago

If the effective resistance of three resistors 3 ohms,5 ohms and Rohms connected in series
is 14 ohms, the value of 'R' is :

a) 6 ohms
b) 2 ohms
c) 4 ohms
d) 1 ohms​

Answers

Answered by aryan073
5

Question :

If the effective resistance of three resistors 3ohms, 5ohms, and R ohms connected in series is 14ohms, the value of R is :

To find :

The value of R=?

Formula :

➡ When three resistors are connected in series then the effective resistance is :

\\ \large\red\bigstar\boxed{\sf{R_{effective \: resistance } = R_1+R_2+R_3}}

➡ when three resistors are connected in parallel then the effective resistance is:

\\ \large\red\bigstar\boxed{\sf{R_{effective \: resistance } = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} } }

Solution :

\red{\bf{Given}} \begin{cases} \sf{ R_1=3ohms} \\ \sf{R_2= 5ohms} \\ \sf{R_3=Rohms} \\ \sf{Effective \: resistance =14 ohms} \end{cases}

\\ \implies\large\sf{R_{effective \: resistance }= R_1 +R_2 +R_3 }

➡ Substitute the given values :

\\ \implies\large\sf{ R_{effective \: resistance }= 3+5+R_3}

\\ \implies\large\sf{ 14=8+R_3}

\\ \implies\large\sf{14-8-R_3 =0}

\\ \implies\large\sf{ R_3=14-8}

\\ \implies\large\sf{R_3=6ohms}

\\ \therefore\large\boxed{\underline{\sf{R_3=6ohms}}}

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➡ Option (1) 6 ohms is correct answer ⛄

Answered by anjali1307sl
1

Answer:

The value of the 'R' of the third resistor = 6\Omega.

Therefore, option a) 6ohms is correct.

Step-by-step explanation:

Given data,

The given resistance of the resistor 1, R₁ = 3\Omega

The given resistance of the resistor 2, R₂ = 5\Omega

The given resistance of the resistor 3, R₃ = R\Omega

The effective resistance of the given three resistors connected in series = 14\Omega

The value of the resistance of the resistor 3, R₃ = R\Omega =?

As we know, if the resistors are connected in series then their effective resistance will be:

  • R_{effective} = R_{1}  + R_{2}  + R_{3}

After putting the values of the given resistances in the above-mentioned formula, we get:

  • 14 = 3+5+R
  • R = 14-8
  • R = 6\Omega

Hence, the value of the 'R' of the third resistor = 6\Omega.

#SPJ3

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