Math, asked by vasanthnatarajan, 2 months ago

If the Eigenvalues of A of order 3x3 are 2,3 and 1,then find the Eigenvalues of adjoint of A.​

Answers

Answered by pulakmath007
8

SOLUTION

GIVEN

Eigen values of A of order 3x3 are 2,3 and 1

TO DETERMINE

Eigen values of adjoint of A.

CONCEPT TO BE IMPLEMENTED

If  \sf{ { \lambda}_{1}, {\lambda}_{2},..., {\lambda}_{n}} are eigen values of a n × n non singular matrix A then the eigen values of adj A are

 \sf{ { c{\lambda}_{1}}^{ - 1} , c{{\lambda}_{2}}^{ - 1} ,..., c{{\lambda}_{n}}^{ - 1} }

Where  \sf{ c = { \lambda}_{1} {\lambda}_{2} \times ... \times  {\lambda}_{n}}

EVALUATION

Here it is given that Eigen values of A of order 3x3 are 2,3 and 1,

So the Eigen values of adjoint of A

= 2 × 3 , 3 × 1 , 2 × 1

= 6 , 3 , 2

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Answered by ravindrakumar746182
0

Answer:

Step-by-step explanation:

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