Question

If the electric field is given by 6î +3j + 4k calculate the electric flux through a surface of
area 20 units lying in YZ-plane.

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Answer 1

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Refer to the attachment..

Answer 2

Answer:

$\phi$ (Electric flux) =  120 V-m

Explanation:

We are given that the electric field is given by:

E = 6i + 3j +4k

And the area of the square is 20 units,

So dA = 20 units

We know that-

$\phi = EdAcos\theta$

We are also told that the square lies along the Y-Z plane, so if we draw a diagram, we would get to know that if the square lies along the Y-Z plane only the X-component of the electric field would pass through the area of the square.

So we are only going to consider the 6i part of the electric field.

Therefore,

$\phi = 6 * 20 cos0$     (cos0, Since the direction of the area vector of the square and the direction of the electric field passing through the square, is the same.)

So,

$\phi = 120 * 1 = 120 V-m$     (cos0 = 1)