Question

If the electric-field magnitude in the conductor is 1.28 V/m, what is the total
current?
1) 150 A
2) 172 A
3) 235 A
4) 100 A​

Answer 1

Complete Question:

An electrical conductor designed to carry large currents has a circular cross-section of 2.50mm in diameter and is 14.0m long. The resistance between its ends is 0.104Ω

If the electric-field magnitude in the conductor is 1.28 V/m, what is the total

current?

1) 150 A

2) 172 A

3) 235 A

4) 100 A​

Answer:

The total current is 172.3 A.

Explanation:

Given Parameters :
Electric Field (E) =  1.28 V/m

Resistance (R) = 0.104 Ω

Length (l) = 14 m

To Be Calculated:
The total Current

Solution:

We have,

Electric Field is given by the Voltage (V) upon the distance between the point (d).

Thus, The formula for Electric Field is given by,

E = V/d

So, It implies that an electric field moves from a higher voltage point to a lower voltage point.

We write, V = E*d = 1.28 * 14 = 17.92 V

Now, Calculating Total Current,

According to Ohm's Law, we have:

V = IR

I = V/R = 17.92/0.104 = 172.3 A

Therefore, the total current is 172.3 A.

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