Question

If the electric flux entering and leaving an enclosed surface of area s respectively are ϕ1 and ϕ2, the magnitude of electric field across the surface will be

Answer 1

Please mark it BRAINLIEST ✏️✏️✏️✏️✏️✏️✏️✏️✏️

Answer 2

Answer:

We know that, electric flux ϕ1 (or electric field lines) entering in a closed surface is -ve and electric flux ϕ2(or electric field lines) leaving a closed surface is +ve.  

Hence, net electric flux through the closed surface,

                   ϕ=ϕ2−ϕ1

Now, according to Gauss' theorem, the net electric flux ϕ passing through a closed surface is equal to the 1/ε0 times of the total charge q, enclosed by surface i.e.

ϕ=q/ε0ϕ2−ϕ1

​=q/ε0

q=ε0(ϕ  2

−ϕ  1  )