Question

If the electrical force of repulsion between two same amount of charges is 10 N, and they are 30000 m apart. What is the magnitude of each charge?

Answer 1

the answer is 0.997 coulombs

Answer 2

Answer:

• Each charge is of 1.05 Coulombs approximately.

Explanation:

Electrical force of repulsion between two same amount of charges is 10 N. Two charges are 30000 m apart.

• Force of repulsion between charges, F = 10 N
• Distance between the charges, r = 30000 m
• Two charges are equal in amount i.e., q₁ = q₂  

We need to find

• the magnitude of each charge, Let q₁ = q₂ = q

Using the formula for electrostatic force

→ F = k q₁ q₂ / r²

[ Where F is electrostatic force between two charges q₁ and q₂, having a distance r between them, k is coulomb's constant i.e., k = 1/(4πε₀) = 8.98 × 10⁹ Nm²C⁻² ]

→ F = k q q / r²     [ ∵ q₁ = q₂ = q ]

→ F = k q² / r²

→ 10 = 8.98 × 10⁹ × q² / (30000)²

→  10 = 9.978 × q²

→ q² = 10/9.978 = 1.1

→ q = 1.05 C  (approx.)

Therefore,

• Each charge is of 1.05 Coulombs. (approximately)