Question

if the electron can be located in the orbit with in 0.1 Å what is the uncertainty in its velocity. ​

Answer 1

Answer:

I’m to calculate the uncertainty in the velocity of an electron given the following information:

The electron is moving at 1.0 x 106 m/s

its mass is 9.11 x 10-31 kg.

the position is to be located within 6.4 x 10-12 m.

I know I’m to use the equation (Δx) (Δp) > h/4π(pi)

I believe I know that p = momentum which = mass x velocity =(9.11 x 10-31 kg) (1.0 x 106 m/s) = 9.11 x 10-25 kg·m/s

But I’m given the Δx (position uncertainty) which is 6.4 x 10-12 m, I know h= 6.626 x 10-34 (kg·m2/s2)·s

So I’m stuck not knowing what I’m actually solving for.

Clarification needed because unfortunately all the examples in the textbook are not for this type of problem.

Answer 2

Answer:

5.8 x 10⁶

Explanation:

∆x . m∆v = h/4π = 0.527/10³⁴

= 0.1/10¹⁰ . 9/ 10³¹.∆v = 0.527/10³⁴

= ∆v = 0.527/10³⁴ x 10³¹/9 x 10¹⁰/0.1

= ∆v = 5.8 x 10⁶

.... hope it helps you....