Question

If the electron of hydrogen atom takes 3.2*10^-17 sec to complete one revolution, then how much current is consituted

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

If the electron of hydrogen atom takes ${\sf 3.2×10^{-17}\:sec}$ to complete one revolution, then how much current is consituted

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large{\rm We \: Know \: That - }$

$\large{\boxed{\bf \blue{I = \dfrac{Q}{t}}}}$

t = ${\sf 3.2×10^{-17}\:sec}$

And charge on one electron is ${\sf 1.6×10^{-19}C}$.

So ,

$\implies{\sf I = \dfrac{1.6×10^{-19}}{3.2×10^{-17}} }$

$\implies{\sf I = 0.5×10^{-19+17} }$

$\implies{\sf I = 0.5×10^{-2}}$

$\implies{\bf \red{Current\:(I )= 5×10^{-3}\:A}}$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Current is consituted ${\bf \red{Current\:(I )= 5×10^{-3}\:A}}$.