If the electronic charge is 16x10°C, then the number of electrons passing through a section of wire per second, when the wire carries a current of 2 ampere is
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Answer:
Given : e=1.6×10
−19
C I=2 A t=1 s
Using I=
t
ne
∴ Number of electrons n=
e
It
=
1.6×10
−19
2×1
=1.25×10
19
electrons
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