If the elemental composition of butyric acid is found to be 54.2% C, 9.2% H
and 36.6% O. What will be its molecular formula if its molecular mass is 88u?
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Explanation:
I think this is correct
Weight of emperical formula=12×2+1×4+16=44
Given molecular weight =88 which is double of emperical weight. Therefore molecular formula is C4H6O2.
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