Question

If the emf of a battery is 9 V, how much energy is converted from chemical to electrical when 2 C of charge flow?​Please answer this.

Answer 1

Answer:-

• Potential Difference=V=9V
• Charge=Q=2C
• Work done=Energy converted=W=?

We know that

$\boxed{\sf W=\dfrac{V}{Q}}$

$\\ \sf\longmapsto W=\dfrac{9}{2}$

$\\ \sf\longmapsto W=4.5J$

$\\ \underline{\boxed{\bf{\therefore Energy\:Converted=4.5J.}}}$

Note:-

SI units

• Work done=Joules(J)
• Charge=Coulomb(C)
• Potential difference=Volts(V)