if the end term of an ap is given by (-4n+15)find the sum of first 20 terms of this AP.
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solution :-. Given Tn = (-4n+15)
T1 = -4*1 + 15 = 11 , T1 = a = first term .
T2 = -4*2 +15 = 7
Common difference'd' = 7-11 = -4
S20 = n/2 {(2a+(n-1)d}
S20 = 20/2(2* 11 + (20-1)-4}
S20 = 10 (22 -76)
S20 = 10(-54)
S20 = -540 Answer .
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