Question

if the end term of an arithmetic progression is 4 and square - 1 then the 8th term is ​

Answer 1

Answer:

255

Step-by-step explanation:

${n}^{th} term = 4 {n}^{2} - 1 \\ a8 = 4 {(8)}^{2} - 1 \\ = 4(64) - 1 \\ = 256 - 1 \\ = 255$

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