Question

If the energy difference between two laser levels if 0.117ev then find the frequency of laser light

Answer 1

we know that E=hn
Given E=0.117ev
h=6.625*10 (-34)
n=0.117/6.625*10 (-34)

Answer 2

Answer:

The frequency of laser light with a difference between two laser levels of 0.117 eV is 28.25 × 10¹².

Explanation:

The energy difference between two levels of laser is given 0.117 eV when a particle cross this energy difference between lasers it emits light of a certain wavelength and frequency.

we have a relation between the  frequency  and energy as                                  

  E = hv

$0.117 eV =6.626 v \times 10^{-34} v$

$v= \frac{0.117\times1.6\times10^{-19} }{6.626\times10^{-34} }\\\\v= 0.02825\times 10 ^{15}\\\\v= 28.25\times10 ^{12}$

Hence the  frequency of laser light is 28.25 × 10¹².