If the energy in the first excited state in hydrogen atom is 23.8 ev then the potential energy of a hydrogen atom in the ground state can be assumed to be
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total energy of any level in Hdrogen atom is E = -13.6/n2
E (ground state) = -13.6ev
E(first exited state) = -13.6/4 ev
potential of ground state = -27.2ev
if potential of ground state is 0 then we have to add +27.2 , by this method we
can make ground state potential 0 ...
now add this potential to energy of each state this will give the final energy of that state ...
E(first exited state) = -13.6/4 + 27.2 = 23.8ev
E (ground state) = -13.6ev
E(first exited state) = -13.6/4 ev
potential of ground state = -27.2ev
if potential of ground state is 0 then we have to add +27.2 , by this method we
can make ground state potential 0 ...
now add this potential to energy of each state this will give the final energy of that state ...
E(first exited state) = -13.6/4 + 27.2 = 23.8ev
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