Question

if the energy of an electron in the first orbit of h-atom is –313.6 kcal/mol, then energy of electron in the second orbit of helium will be :

Answer 1

Answer: E = -313. 6kcal Z2/n2

Explanation:

E = -313. 6 x 2^2/2^2

E = - 313.6 KCal/mole