Question

If the energy of an electron in the second bohr orbit of h atom is -e, what is the energy of the electron in the bohrs first orbit

Answer 1

-2e since the max. Elections accommodated in the first shell is 2.

Answer 2

Answer: -4e

Explanation: $E=\frac{-E_0\times Z^2}{n^2}$

E= energy

n= orbit

Z= atomic number = 1

For  Bohr's second orbit, n=2 and for hydrogen, Z=1Thus $-e=\frac{-E_0\times 1^2}{2^2}=$

$E_0=4e$

for Bohr's first orbit, n=1

$E=\frac{-E_0\times Z^2}{n^2}$

$E=\frac{-(4e)\times 1^2}{1^2}=-4e$