Question

If the energy of the electron in bohrs first orbit is e then the energy of electron in second orbit i

Answer 1

The formula defining the energy levels of a Hydrogen atom are given by the equation: E = -E0/n2, where E0 = 13.6 eV (1 eV = 1.602×10-19 Joules) and n = 1,2,3… and so on. The energy is expressed as a negative number because it takes that much energy to unbind (ionize) the electron from the nucleus.

Answer 2

Answer:

heya..

Third Bohe orbit corresponds to principle quantum number, n = 3. Now, energy of anelectron in n = n is En= - 13.6/ n^2 eV for hydrogen atom. Now, in Bohr's theory we come across the result:En= (1/2) ( potentialenergy). Therefore, (1/2)(potential energy )=-(13.6/9)eV.

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