If the engine of a car provides an acceleration of 2m/s square to start it from rest ,then assuming the mass to be roughly 1000kg and frictional force 15N,calculate
a) velocity after 10 s.
b) final velocity of the car when the engine is on after 15s.
c)force provided by the engine.
d) after 15s ,the net force provided by the engine
Answers
Explanation:
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Answer:
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Explanation:
a + t = 15
_________
| |
| | -> v (final velocity)
| |
_________
Suppose the above figure is the engine. Then final velocity v is acting on it.
So now, applying the equation of motion,
v - u = at
or, v - 0 = 2 × 15
or, v - 0 = 30 m/s.
Now,
see the diagram below :
__________________
| |
m
|_________________ | -> v (final velocity)
Force acting on the left side of the above object is Fr.
________
| |
| | -> v¹ = 0
________
Force acting on the left side of the object is H.
Now,
a¹ = - fr/m
or, = - 15/1000
or, = - 15 × 10^-³ m/s²
Now again, v¹ - v = a¹t²
write t of t² in subscript form)
or, 0 - 30 = - 15 × 10^-³ t² (here also write t in subscript form)
or, t² (here also) = 30/ 15 × 10³
or, 2 × 10³ secs.
or, 2000 secs.