Question

If the enthalpy of formation of N20(9), N204(9), CO(g) and CO2(g) is 800, 15, -100, and -
400 kJ/mol respectively, then A,H for the given reaction is
N204(9)+300(g) →N20(9)+3C02(9)
+90 kJ/mol
0-115 kJ/mol
+115 kJ/mol
0-500 kJ/mol

Answer 1

i Think So It Will Help U ,

0-500 kJ/mol

Answer 2

Answer:

0-500kJ/mol

Explanation:

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