if the equal x^2-bx+1=0 does not posses real roots then (a) -3<b<3 (b) -2<b<2 (c) b>2 (d) b> -2
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0
If equation x
2
−bx+1=0 does not have real roots, then
Δ<0⟹b
2
−4<0
(b+2)(b−2)<0
∴−2<b<2
Answered by
1
Answer:
Correct option is
B
−2<b<2
If equation x
2
−bx+1=0 does not have real roots, then
Δ<0⟹b
2
−4<0
(b+2)(b−2)<0
∴−2<b<2
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