If the equation 2x^2+2hxy+py^2-2x+6y-4=0 is a circle then find p and h
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2x^2+2hxy+py^2-2x+6y-4=0
= x² +4x -y² -6y +k
= x² + 4x +2² - (y² +6y +3²) ------(1)
= (x+2)² - (y+3)²
= [x+2+y+3] [ x+2 -y-3]
=(x+y+5) ((x-y-1)
from (1)
k = 2² -3² = 4-9 =-5
Step-by-step explanation:
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