Question

if the equation 4x^2 + hxy +y^2 = 0 represents two coincident lines, then h =

A) ±2
B) ±3
C)±4
D)±5
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Answer 1

Answer:

Using(a+b)^2=a^2+b^2+2ab
We get =(2x+y)^2
=4x^2+4xy+y^2
So value of h=4

Answer 2

Answer:

h = ±2

Step-by-step explanation:

Given: equation 4x^2 + hxy +y^2 = 0 represents two coincident lines.

To find value of h.

We know that two lines are coincident when, h^2=ab.

Here, a= 4,b=1

h^2=4

h=±2

So, if 4x^2 + hxy +y^2 = 0 represents two coincident lines then h = ±2.

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