Question

If the equation 6x+py=5 & 3x+4y=2 have no solution,then find the value of 'p'?

Answer 1

6x+py=5
6x+py-5=0
ax+by+c=0; here a=6, b=p, c=-5
3x+4y=2
3x+4y-2=0
here a=3, b=4, c=-2
if they have no solution then a1/a2=b1/b2≠c1/c2
then substitute the values
we get 6/3=p/4≠-5/-2
the value of p is 8

Answer 2

If two equations ax+by=c and px + qy = r has no solution then 
$\frac{a}{p} = \frac{b}{q}$

6/3 = p/4
2 = p/4
p = 8