Question

if the equation (a2+b2)x2-2(ac+bd)x+c2+d2=0 has equal roots. find ab and ad

Answer 1

Answer:

a

2

+b

2

)x

2

−2(ac+bd)x+(c

2

+d

2

)=0 has equal roots.

Therefore, discriminant =0

Thus [2(ac+bd)]

2

+4(a

2

+b

2

)(c

2

+d

2

)

⇒a

2

c

2

+b

2

d

2

+2ac.bd=a

2

c

2

+a

2

d

2

+b

2

c

2

+b

2

d

2

⇒(ad−bc)

2

=0$

⇒ad−bc=0

⇒ad=bc

Answer 2

Answer:

ohh......

sorry I didn't know that