Question

If the equation ax^2 + 2x- 2 =0 has real and distinct roots then the value of a is

Answer 1

Answer:ax^2 + 2x - 2 = 0

it means that

b^2 - 4ac = 0, a = a, b = 2, c = -2

substituting the values,

4 + 8a = 0

8a = -4

a = -4/8

a = -1/2

explanation:

to check whether the answer is right substitute the value of ‘a’ in

b^2 - 4ac = 0

Hope it helps

Answer 2

Answer:

a = - 1 / 2

Step-by-step explanation:

Given : If the equation a x ^ 2 + 2 x - 2 = 0 has real and distinct roots

To find : What is the  value of a

Solution :

a x ^ 2 + 2 x - 2 = 0

it means that

b ^2 - 4 a c = 0 , a = a , b = 2 , c = - 2

substituting the values,

4 + 8 a = 0

8 a = - 4

a = - 4 / 8

a = - 1 / 2

to check whether the answer is right substitute the value of ‘ a ’ in

b ^ 2 - 4 a c = 0

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