If the equation ax^2 + 2x + a = 0 has equal root , then find the value of a .
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Answer:
a=1
Step-by-step explanation:
ax²+2x+a=0
a=a, b=2, c=a
Discriminant=0
b²-4ac=0
(2)²-4(a)(a)=0
4-4a²=0
4(1-a²)=0
1-a²=0/4
1-a²=0
(-a²)=(-1)
a²=1
a=√1
a=1
Therefore, the value of a is 1.
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