if the equation ax2+2x+a=0 has two distinct root ,if
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Answer:
CORRECT QUESTION:
If the equation ax²+2x+a=0 has distinct roots,find the value of a.
Solution
Given Equation,
ax²+2x+a=0
On comparing with Ax²+Bx+C=0,
A=a,B=2 and C=a
Given that the above equation has distinct roots
Implies,
D>0
→B² - 4AC>0
→2² -4a² > 0
→4 - 4a² > 0
→1 - a² > 0
→ 1 > a²
→a < 1
For a < 1,the above equation has distinct and real roots
Step-by-step explanation:
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