Question

if the equation for displacement of two particles executing SHM is given as y1=2Sin(10t+è) and y2=3cos10t respectively, then the phase difference between velocities of two particles will be...​

Answer 1

Answer:

Phase difference of two velocity is given as

$\delta \phi = \phi - \frac{\pi}{2}$

Explanation:

As we know the the position of two objects given in the equation as

$y_1 = 2 sin(10 t + \phi)$

$y_2 = 3 cos(10 t)$

we can write 2nd equation as

$y_2 = 3 sin(10t + \frac{\pi}{2})$

now we know that velocity of two objects is rate of change in position

so we have

$v_1 = 20 cos(10 t + \phi)$

$v_2 = 30 cos(10 t + \frac{\pi}{2})$

now phase difference of two velocity is given as

$\delta \phi = (10t + \phi) - (10t + \frac{\pi}{2})$

$\delta \phi = \phi - \frac{\pi}{2}$

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Topic : Phase difference

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