Physics, asked by Ridikulus, 1 year ago

If the equation for the angular displacement of a particle moving on a circular path is given by ø = 2t3 + 0.5, where ø is in radians and t is in seconds, then the average angular velocity of the particle after 2 seconds from its start is

Answers

Answered by sharry10
30
the answer is 24
differentiate the above equatiin w.r.t t and put t=2
Answered by shirleywashington
72

Answer:

Angular velocity, \omega=24\ rad/s

Explanation:

Angular displacement of a particle moving on a circular path is given by,

\theta=2t^3+0.5

Where

\theta is in radian and t is in seconds.

We know that angular velocity is defined as the rate of change of angular displacement. Mathematically, it can be written as :

\omega=\dfrac{d\theta}{dt}

\omega=\dfrac{d(2t^3+0.5)}{dt}

\omega=6t^2

Angular velocity at t = 2 seconds will be :

\omega=6(2)^2=24\ rad/s

So, the angular velocity of the particle after 2 seconds from its start is 24 radian/s. Hence, this is the required solution.

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