if the equation for the displacement of a particle moving along a circular path is given by theta = to 2 t³ + 0.5 where theta is in radius and t is in seconds then the angular acceleration of the particle at t = 2s is
(a) 8 rads-2
(b) 12rads-2
(c) 24rads-2
(d) 36rads-2
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Answer:
Correct option is C)
option c 24 rad s
ω=
dt
dq
=
dt
d
(2t
3
+0.5)=6t
2
t=2s,ω=6×2
2
=24rad/s
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