If the equation (k’ - 3k + 2)x’ +(k’ - 5k + 4)x + (k’ - 6k+5)=0 is an identity, then the value of k is
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If the equation
(k
2
−5k+6)x
2
+(k
2
−3k+2)x+(k
2
−4)=0
is satisfied by more than two values of x, then determine the value of k.
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