if the equation kx^2-2kx +6=0 has equal roots then find the value of k
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Answered by
10
Heya!!!
Here's your answer friend,
kx² - 2kx + 6 = 0
have equal roots
therefore on comparing above equation we get a = K b = -2k c = 6
b² - 4ac = 0
(-2k)² - 4 K x 6
4k² - 24k
k² = 24k/4
K = 6 or K = 0
Hope you like it : )
Here's your answer friend,
kx² - 2kx + 6 = 0
have equal roots
therefore on comparing above equation we get a = K b = -2k c = 6
b² - 4ac = 0
(-2k)² - 4 K x 6
4k² - 24k
k² = 24k/4
K = 6 or K = 0
Hope you like it : )
Answered by
12
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YOUR ANSWER ⬆
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YOUR ANSWER ⬆
I HOPE YOU FIND IT HELPFUL
#LAKSHMI.... :-)
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