Question

if the equation kx^2 -2kx +6=0 has equal roots then find the value of k

Answer 1

Hey friend!! here is your answer

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⭕️ Condition for equal roots is b^2-4ac=0

✔️a=k , b=-2k & c=6

✅(-2k)^2-4(k)(6)=0

✅4k^2-24k=0

✔️4k^2=24k

✔️4k^2/k=24

✅4k=24

✔️k=24/4

⭕️k=6

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⭐️hope it helps you⭐️

Answer 2

For equal roots,

b^2 - 4ac = 0

Here, p(x) = kx^2 - 2kx + 6

a = k , b = -2k , c = 6

b^2 - 4ac = 0

(-2k)^2 - 4(k)(6) = 0

4k^2 - 24k = 0

k(4k - 24) = 0

4k - 24 = 0

4k = 24

k = 24/4

k = 6